(x-3)(2x^2+4x-1)=

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Solution for (x-3)(2x^2+4x-1)= equation: 


Simplifying
(x + -3)(2x2 + 4x + -1) = 0

Reorder the terms:
(-3 + x)(2x2 + 4x + -1) = 0

Reorder the terms:
(-3 + x)(-1 + 4x + 2x2) = 0

Multiply (-3 + x) * (-1 + 4x + 2x2)
(-3(-1 + 4x + 2x2) + x(-1 + 4x + 2x2)) = 0
((-1 * -3 + 4x * -3 + 2x2 * -3) + x(-1 + 4x + 2x2)) = 0
((3 + -12x + -6x2) + x(-1 + 4x + 2x2)) = 0
(3 + -12x + -6x2 + (-1 * x + 4x * x + 2x2 * x)) = 0
(3 + -12x + -6x2 + (-1x + 4x2 + 2x3)) = 0

Reorder the terms:
(3 + -12x + -1x + -6x2 + 4x2 + 2x3) = 0

Combine like terms: -12x + -1x = -13x
(3 + -13x + -6x2 + 4x2 + 2x3) = 0

Combine like terms: -6x2 + 4x2 = -2x2
(3 + -13x + -2x2 + 2x3) = 0

Solving
3 + -13x + -2x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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